SOLUTION: Two points have coordinates A(1,-3) and B(-3,5).Find the equation of the perpendicular bisector of AB.Find the coordinates of the point P on the line y = x - 2 if P is equidistant

Algebra ->  Triangles -> SOLUTION: Two points have coordinates A(1,-3) and B(-3,5).Find the equation of the perpendicular bisector of AB.Find the coordinates of the point P on the line y = x - 2 if P is equidistant       Log On


   

Question 1177428: Two points have coordinates A(1,-3) and B(-3,5).Find the equation of the perpendicular bisector of AB.Find the coordinates of the point P on the line y = x - 2 if P is equidistant from A and B.Calculate also the length of AP.
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!

Hi
Reply Previously Posted 
 A(1,-3) and 
 B(-3,5) Midpoint is P(-1, 1)  and m = -8/4 = -2 (Line segment AB)


the equation of the perpendicular bisector:
 y - 1 = (1/2)(x + 1)
  y = (1/2)x + 3/2 Green

 y = x - 2 Blue
 P(7,5) is the same distance from P(A)  and P(B)
D = +sqrt+%28+%28x%5B1%5D-x%5B2%5D%29%5E2%2B+%28y%5B1%5D-y%5B2%5D%29%5E2+%29+
  AP = sqrt(36 + 64) = 10
Wish You the Best in your Studies.