Question 1177323: How many liters of a 20% acid solution must be mixed with 15 liters of a 60% solution to create 40 liters of a 35% solution? Answer by math_helper(2461) (Show Source):
This problem is over-constrained. In other words, the answer is easily determined by subtracting the starting 15L from the final 40L to
get . A better problem would not specify how many liters the final mixture has and would simply ask how many liters need to be added to bring the concentration down to 35%.
The problem would ordinarily be solved as follows:
Let x = amount of 20% acid solution to be mixed in
