SOLUTION: Find four consecutive odd integers with a sum of-8. Let 2n+1 represent the first odd integer.

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Question 1177299: Find four consecutive odd integers with a sum of-8. Let 2n+1 represent the first odd integer.
Found 2 solutions by josgarithmetic, greenestamps:
Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
These integers
system%282n%2B1%2C2n%2B3%2C2n%2B5%2C2n%2B7%29


Sum is -8:
8n%2B16=-8
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n%2B2=-1
n=-3, and you can find your odd integers from this.
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Answer by greenestamps(13200) About Me  (Show Source):
You can put this solution on YOUR website!


The average of the four integers is -8/4 = -2.

Then, since the four integers are equally spaced, they must be the four odd integers closest to -2. The two integers either side of -2 and closest to -2 are -5, -3, -1, and 1.