SOLUTION: Find a polynomial f(x) of degree 3 that has the indicated zeros and satisfies the given condition. −3, −2, 0; f(−4) = 32

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: Find a polynomial f(x) of degree 3 that has the indicated zeros and satisfies the given condition. −3, −2, 0; f(−4) = 32       Log On


   

Question 1177241: Find a polynomial f(x) of degree 3 that has the indicated zeros and satisfies the given condition.
−3, −2, 0; f(−4) = 32
Found 2 solutions by josgarithmetic, Solver92311:
Answer by josgarithmetic(39620) About Me  (Show Source):
You can put this solution on YOUR website!
f%28x%29=ax%28x%2B3%29%28x%2B2%29
and
f%28-4%29=a%2A%28-4%29%28-4%2B3%29%28-4%2B2%29=32, and you can solve the factor, a.

Answer by Solver92311(821) About Me  (Show Source):
You can put this solution on YOUR website!



If a polynomial function has a zero at some number , then must be a factor of the polynomial. Hence, the desired polynomial is:





Then


Do the arithmetic, solve for , plug that value back into , and simplify.

John

My calculator said it, I believe it, that settles it

From
I > Ø