Hi
NOrmal Distribution: μ = 20min σ = 5min
Using TI or similarly an inexpensive calculator like a Casio fx-115 ES plus
a P( 18 < x < 24) = normalcdf(18,24, 20, 5) = .4436
b. P( 22 < x < 30)= normalcdf(22,30, 20, 5) = .3218
c. P( x > 12) = 1 - P(x ≤ 12) - 1 - normalcdf(-9999, 12, 20,5) = 1-.0548 = .9452
d. z = invNorm(.05) = 1.645= (x-20)/5 ⇒ x = 28.225min
Wish You the Best in your Studies.