SOLUTION: How many different six-place license plates are possible if the first three places and the last place are to be occupied by letters and the fourth and fifth places are to be occup

Algebra ->  Probability-and-statistics -> SOLUTION: How many different six-place license plates are possible if the first three places and the last place are to be occupied by letters and the fourth and fifth places are to be occup      Log On


   



Question 1177137: How many different six-place license plates are possible if the first three places and the last
place are to be occupied by letters and the fourth and fifth places are to be occupied by
numbers?
thanks again for helping answer :)

Found 2 solutions by greenestamps, ikleyn:
Answer by greenestamps(13200) About Me  (Show Source):
You can put this solution on YOUR website!


Multiply the numbers of choices for each place -- 26 choices for each place where each letter goes; 10 choices for each place where a digit goes:

26*26*26*10*10*26

Use a calculator....


Answer by ikleyn(52797) About Me  (Show Source):
You can put this solution on YOUR website!
.

26 English alphabet letters in four positions and 10 digits in two positions provide  


    26%5E4%2A10%5E2  = 45697600


different possible six-place license codes.

Solved, answered and explained. And completed.