SOLUTION: A random sample of 80 voters found that 56 were going to vote for a certain candidate. Find the 90% confidence interval for the population proportion of voters who will vote for th

Algebra ->  Probability-and-statistics -> SOLUTION: A random sample of 80 voters found that 56 were going to vote for a certain candidate. Find the 90% confidence interval for the population proportion of voters who will vote for th      Log On

Hi
n > 60    x̄ = 56/80 = .7
two tailed: 90% confidence interval:  z = 1.645

ME = 1.645*sqrt((.7*.3)/80)) = .0843

.7- ME <  < .7 + ME

CI:  (.62, .78)

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