Question 1177092: Suppose we toss two coins and suppose that each of the four points in the sample space
S = {(H, H ), (H, T ), (T, H ), (T, T )} is equally likely. Let the events be A = {(H, H ), (H, T )}
and B = {(H, H ), (T, H )}. Find P(A ∪ B)
Found 2 solutions by ikleyn, mccravyedwin:
Answer by ikleyn(52879)   (Show Source):
You can put this solution on YOUR website! .
A U B = { (H,H), (H,T), (T,H) }.
Therefore, P(A U B) = P(H,H) + P(H,T) + P(T,H) = 0.25 + 0.25 + 0.25 = 0.75. ANSWER
Solved.
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Answer by mccravyedwin(409)  (Show Source):
You can put this solution on YOUR website!
A ∪ B contains all the elements in S except (T, T ). The probability of
(T, T} is 1/4, So the probability of A ∪ B is 1 - 1/4 = 3/4.
Edwin
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