SOLUTION: The closed form sum of
12 [ 1^2 * 2 + 2^2 * 3 + ... + n^2 (n+1) ]
for n <= 1 is n(n+1)(n+2)(an+b). Find an + b.
Algebra ->
Sequences-and-series
-> SOLUTION: The closed form sum of
12 [ 1^2 * 2 + 2^2 * 3 + ... + n^2 (n+1) ]
for n <= 1 is n(n+1)(n+2)(an+b). Find an + b.
Log On
Obviously, from the form of the expression, the statement of the problem is supposed to say that the closed form of the sum is for n >=1 -- not for n <= 1.
There are only two unknowns in the problem -- a and b. So two equations in a and b should be enough to solve the problem.
