SOLUTION: A fair die is tossed twice.find the probability of getting 4,5, or 6 on the first toss and a 1,2,3 or 4 on the second toss.

Hi
the probability of getting 4,5, or 6 on the first toss 
and a 1,2,3 or 4 on the second toss.

 P = 12/36 = 1/3

(1,1) (1,2) (1,3) (1,4) (1,5) (1,6)

(2,1) (2,2) (2,3) (2,4) (2,5) (2,6) 

(3,1) (3,2) (3,3) (3,4) (3,5) (3,6) 

(4,1) (4,2) (4,3) (4,4) (4,5) (4,6) 

(5,1) (5,2) (5,3) (5,4) (5,5) (5,6) 

(6,1) (6,2) (6,3) (6,4) (6,5) (6,6)

Wish You the Best in your Studies.

The probability of getting 4, 5, or 6 on the first toss  is   = .


The probability of getting 1, 2, 3, or 4 on the second toss is   = .


The outcomes of the first and the second toss are INDEPENDENT, so the final answer is the product


    P =  = .    ANSWER