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Question 1177029: Kate, Melissa, Ann and Jack shared a jar of biscuits. Kate took 30% of the biscuits and Melissa took 25% of the biscuits. Jack took the remaining 80 biscuits. Ann took 20 more biscuits than Melissa. What percentage of the biscuits did Ann take from the jar?
Found 3 solutions by ikleyn, josgarithmetic, greenestamps:
Answer by ikleyn(52781)   (Show Source):
You can put this solution on YOUR website! .
Kate, Melissa, Ann and Jack shared a jar of biscuits. Kate took 30% of the biscuits and
Melissa took 25% of the biscuits. Jack took the remaining 80 biscuits. Ann took 20 more biscuits than Melissa.
What percentage of the biscuits did Ann take from the jar?
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As the problem is worded, printed, posted and presented, it MAKES no SENSE.
Good only for re-cycling.
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Comment from student: Wow thanks and if it makes no sense then why did my teacher post this for us to solve WE ARE YEAR 6
My response : Show my comment to your teacher and then ask him (or her) why he (or she) posts you nonsensical problems.
Asking me about it, you address your question to wrong person.
At the end, inform me on what you learned from your conversation with the teacher.
Answer by josgarithmetic(39617)  (Show Source):
You can put this solution on YOUR website! Not sure if assigning a variable to "what percentange did Ann take" is the easiest or best way, but
b, number of biscuits initially in the jar
PERSON BISCUITS TAKEN
Kate 0.3b
Melissa 0.25b
Jack 80
Ann 0.25b+20
SUM b
Solve this equation to find how many biscuits were in the jar at the start:
Once b is found, get Ann's percentage of biscuits according to
 .
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500 biscuits in the jar? Maybe these are small cookies in a very big jar.
Answer by greenestamps(13200)  (Show Source):
You can put this solution on YOUR website!
I am amazed at how often a problem given by a teacher or found in a textbook makes no sense....
Kate took some of the biscuits; then Melissa took some; then Jack took the rest.
That means there are none left, so Ann couldn't have taken any.
Absurd....
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