SOLUTION: Topic: Similarities (I don't know if proofs is the right section) Circle A has a radius of 28 inches, and circle B has a 44-inch radius... https://media.discordapp.net/attachme

Algebra ->  Geometry-proofs -> SOLUTION: Topic: Similarities (I don't know if proofs is the right section) Circle A has a radius of 28 inches, and circle B has a 44-inch radius... https://media.discordapp.net/attachme      Log On


   

Question 1177022: Topic: Similarities (I don't know if proofs is the right section)
Circle A has a radius of 28 inches, and circle B has a 44-inch radius...
https://media.discordapp.net/attachments/802751414874537995/821169693012131850/HNkZEShUBwfFin0x07dqy2tra5ubm8vFypVKrVash3mWx7RzMigzY2Nvxv9vtntr5OByO2dnZxcXFlZWVsrKy9vb2trY2i8VSXFx.png
Found 2 solutions by MathLover1, ikleyn:
Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!

The length of a direct common tangent to two circles is
CD=sqrt%28d%5E2-%28r%5B1%5D-r%5B2%5D%29%5E2%29
where d is the distance between the centres of the circles, and r%5B1%5D and r%5B2%5D are the radii of the given circles.
given:
r%5B1%5D=28 inches, and r%5B2%5D+=44 inches
+d=90
CD=sqrt%2890%5E2-%2828-44%29%5E2%29
CD=sqrt%288100-256%29
CD=sqrt%287844%29
CD=88.57



Answer by ikleyn(52829) About Me  (Show Source):
You can put this solution on YOUR website!
.

            The question in this post is about the length of the common  INTERIOR  tangent to two non-overlying circles.

            I don't know  (don't sure)  if  @Matlower have read the problem and the question,  at all,
            but she answered  OTHER  question about the length of the common  EXTERIOR  tangent to two cirles.


            So,  her answer/solution is  NOT  RELEVANT  to the problem.


            THEREFORE,  I came to give you the link  (the reference)  to the real source.



See the lesson
    - HOW TO construct a common interior tangent line to two circles
in this site.

The problem 2 of this lesson contains the solution to your problem.

Learn it from there.