SOLUTION: Find the standard form of the equation of the hyperbola with the given characteristics. Vertices: (−5, 5), (5, 5); foci: (−6, 5), (6, 5)

Algebra ->  Trigonometry-basics -> SOLUTION: Find the standard form of the equation of the hyperbola with the given characteristics. Vertices: (−5, 5), (5, 5); foci: (−6, 5), (6, 5)      Log On


   

Question 1177017: Find the standard form of the equation of the hyperbola with the given characteristics.
Vertices: (−5, 5), (5, 5); foci: (−6, 5), (6, 5)
Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!
Standard form:
%28x-h%29%5E2%2Fa%5E2-%28y-k%29%5E2%2Fb%5E2=1
given:
foci: (-6,5), (6,5)
since foci is at (c,5) =>c=6
vertices:(-5,5), (5,5)
since vertices is at (a,5) =>a=5
then
b%5E2=c%5E2-a%5E2
b%5E2=6%5E2-5%5E2
b%5E2=36-25
b%5E2=11
so, your equation is:
x%5E2%2F25-%28y-5%29%5E2%2F11=1