SOLUTION: EVOL is a cyclic quadrilateral, inscribed in a circle with center S. Given that the radius of this circle is 25 in. and angle VEL is 55 degrees. explain your work to find the follo

Algebra ->  Length-and-distance -> SOLUTION: EVOL is a cyclic quadrilateral, inscribed in a circle with center S. Given that the radius of this circle is 25 in. and angle VEL is 55 degrees. explain your work to find the follo      Log On


   



Question 1177016: EVOL is a cyclic quadrilateral, inscribed in a circle with center S. Given that the radius of this circle is 25 in. and angle VEL is 55 degrees. explain your work to find the following measurements.
a)Length of Major Arc VL
b)Angle measure of Minor Arc VL
c)Angle VOL
d)Length of Chord VL

Answer by mccravyedwin(407) About Me  (Show Source):
You can put this solution on YOUR website!

Let the center be K. Draw radii KV and KL [which are 25 in. each. We'll get
that in part d)].  Let's answer part b) first
b)Angle measure of Minor Arc VL
Since inscribed angle VEL is 55°, then 55° is one-half the measure of
its intercepted arc.  So minor arc VL is twice 55°, or 110°.

Let's do part a) next
a)Length of Major Arc VL
The measure of major arc VL = 360°-the measure of minor arc VL 
= 360-°110°=250° 

Let's do part c) next
c)Angle VOL
Since inscribed angle VOL subtends major acc VL, which is 250°, then 250° is
one-half the measure of its intercepted arc. So angle VOL is 125°  
d)Length of Chord VL
Since we found minor arc VL to have measure 110° in part a), Central angle
VKL also has measure 110°.

Now we will draw KP perpendicular to VL.  

 

d)Length of Chord VL
Since triangle VKL is isosceles, KP bisects angle VKL, which is 110°, and
angle VKP is 55°.

sin%28VKP%29=opposite%2Fhypotenuse=VP%2FVK
sin%2855%5Eo%29=VP%2F25
25sin%2855%5Eo%29=VP
20.47880111=VP

Since chord VL is twice VP, chord VL has length 40.95760221,

Edwin