SOLUTION: Let f(x)=4-x^2. The equation of the tangent line to the curve at (1,3) is 2x+y=5. a. What is the slope of the tangent line to the curve at (1,3)? b. What is the derivat

Algebra ->  Linear-equations -> SOLUTION: Let f(x)=4-x^2. The equation of the tangent line to the curve at (1,3) is 2x+y=5. a. What is the slope of the tangent line to the curve at (1,3)? b. What is the derivat      Log On


   

Question 1176982: Let f(x)=4-x^2. The equation of the tangent line to the curve at (1,3) is 2x+y=5.

a. What is the slope of the tangent line to the curve at (1,3)?


b. What is the derivative of the function when x=1?
Found 2 solutions by Solver92311, Alan3354:
Answer by Solver92311(821) About Me  (Show Source):
You can put this solution on YOUR website!



Stop trying to game the system by posting the same question twice.


John

My calculator said it, I believe it, that settles it

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Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
Let f(x)=4-x^2. The equation of the tangent line to the curve at (1,3) is 2x+y=5.

a. What is the slope of the tangent line to the curve at (1,3)?
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The slope is -2, as shown in part b.
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Or,
2x+y=5
y = -2x + 5
Slope = -2
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b. What is the derivative of the function when x=1?
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f'(x) = -2x
f'(1) = -2