You can put this solution on YOUR website! .
Find the probability of throwing a sum of 2 at least 3 times in 9 throws
of a pair of fair dice.
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It is a binomial distribution probability problem.
- number of trials n = 9;
- number of success trial k >= 3;
- Probability of success on a single trial p = 1/36 = 0.027777778 (the case 1+1 = 2).
We need calculate P(n=9; k>=3; p=1/36).
To facilitate calculations, I use an appropriate online (free of charge) calculator at this web-site
https://stattrek.com/online-calculator/binomial.aspx
It provides nice instructions and a convenient input and output for all relevant options/cases.
P(n=9; k>=3; p = 0.027777778) = 0.00158748391, or 0.001587 (rounded). ANSWER
