SOLUTION: y2 - 2x + 6y - 7 = 0 y2 = 16 x y = x2 + 4x + 2 y2 - 6y - 8x +17 = 0 x2 - 6x - y + 11 = 0
Algebra
->
Quadratic-relations-and-conic-sections
-> SOLUTION: y2 - 2x + 6y - 7 = 0 y2 = 16 x y = x2 + 4x + 2 y2 - 6y - 8x +17 = 0 x2 - 6x - y + 11 = 0
Log On
Algebra: Conic sections - ellipse, parabola, hyperbola
Section
Solvers
Solvers
Lessons
Lessons
Answers archive
Answers
Click here to see ALL problems on Quadratic-relations-and-conic-sections
Question 1176785
:
y2 - 2x + 6y - 7 = 0
y2 = 16 x
y = x2 + 4x + 2
y2 - 6y - 8x +17 = 0
x2 - 6x - y + 11 = 0
Answer by
ikleyn(53937)
(
Show Source
):
You can
put this solution on YOUR website!
.
One and ONLY ONE problem/question per post.
It is the RULE, the POLICY and the REQUIREMENT of this forum.
It is written in this page
https://www.algebra.com/tutors/students/ask.mpl?action=ask_question&topic=Equations&return_url=http://www.algebra.com/algebra/homework/equations/
from which you post your problems.
It is assumed that you read these rules before posting.
It is also assumed that you do understand what is written in that page and follow the rules.
Those who violate them, work against their own interests.