SOLUTION: Passing through (5,−3) and perpendicular to the line whose equation is x−5y−4=0 what is the equation in point slope form

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Question 1176780: Passing through (5,−3) and perpendicular to the line whose equation is x−5y−4=0
what is the equation in point slope form
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!


Hi

Previously submitted:

perpendicular to line  x−5y−4=0  0r y = x/5-4/5 , m = 1/5

Slope of New Line is -5  (negative reciprocal)

Passing through (5,−3)

 y + 3 = -5(x - 5)   Point-slope form



  y = -5x -28   Slope Intercept Form

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