SOLUTION: Solve.
An investment is worth $3031 in 1994. By 1998 it has grown to $3759. Let y be the value of the investment in the year x, where x = 0 represents 1994. Write a linear equat
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An investment is worth $3031 in 1994. By 1998 it has grown to $3759. Let y be the value of the investment in the year x, where x = 0 represents 1994. Write a linear equat
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Question 1176775: Solve.
An investment is worth $3031 in 1994. By 1998 it has grown to $3759. Let y be the value of the investment in the year x, where x = 0 represents 1994. Write a linear equation that models the value of the investment in the year x. Found 2 solutions by ewatrrr, ikleyn:Answer by ewatrrr(24785) (Show Source):
Hi
x = 0 represents 1994 (0, 3031)
and
(3759-3031)/3 = 728/3 = 242.67
Let x be the investment in the year x.
y = $3031 + $242.67x
3031 + 3*($242.67) = $3759 checks
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An investment is worth $3031 in 1994. By 1998 it has grown to $3759. Let y be the value of the investment
in the year x, where x = 0 represents 1994. Write a linear equation that models the value of the investment in the year x.
~~~~~~~~~~~~
If $3031 represents the investment amount in 1994
and $3759 represents the investment amount in 1998, 4 years later,
then the rate of linear growth is = 182 dollars per year.
Then the linear equation you request for is
y = 3031 + 182x. ANSWER
