Question 1176746: Maria is 4 times older than his son. After 3 years the sum of their ages will be 38.calculate their presents ages. Found 2 solutions by ankor@dixie-net.com, MathTherapy:Answer by ankor@dixie-net.com(22740) (Show Source):
You can put this solution on YOUR website! I don't think this will have an integer solution, anyway here is a method
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Maria is 4 times older than her son.
m = 4s
After 3 years the sum of their ages will be 38.
(m+3) + (s+3) = 38
m + s + 6 = 38
m + s = 38 - 6
m + s = 32
calculate their presents ages.
replace m with 4s
4s + s = 32
5s = 32
s = 32/5
s = 6.4 yrs old is the son
then
m = 4(6.4) = 25.6 yrs is Maria
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:
Check in the statement
"After 3 years the sum of their ages will be 38."
25.6 + 3 + 6.4 + 3 = 38
You can put this solution on YOUR website!
Maria is 4 times older than his son. After 3 years the sum of their ages will be 38.calculate their presents ages.
