SOLUTION: A punter kicked the football into the air with an upward velocity of 62 ft/s. Its height h in feet after t seconds is given by the function h = - 16t^2+ 62t + 2. What is the maxi
Algebra ->
Customizable Word Problem Solvers
-> Misc
-> SOLUTION: A punter kicked the football into the air with an upward velocity of 62 ft/s. Its height h in feet after t seconds is given by the function h = - 16t^2+ 62t + 2. What is the maxi
Log On
Question 1176734: A punter kicked the football into the air with an upward velocity of 62 ft/s. Its height h in feet after t seconds is given by the function h = - 16t^2+ 62t + 2. What is the maximum height the ball reaches? How long will it take the football to reach the maximum height? How long does it take for the ball to hit the ground? Answer by ankor@dixie-net.com(22740) (Show Source):
You can put this solution on YOUR website! A punter kicked the football into the air with an upward velocity of 62 ft/s.
Its height h in feet after t seconds is given by the function h =-16t^2+ 62t + 2. ​What is the maximum height the ball reaches?
How long will it take the football to reach the maximum height?
:
The max height occurs on the axis of symmetry of this equation, h=-b/(2a)
where a=-16, b= 62
h =
h = 1.9375 seconds
Find the height at 1.9375 seconds
h = -16(1.9375^2) + 62(1.9375) + 2
h = -16(3.754) + 120.125 + 2
h = -60.0625 + 120.125 + 2
h = 62.0625 ft is max height at 1.9375 seconds
:
:
How long does it take for the ball to hit the ground?
then h = 0
-16t^2 + 62t + 2 = 0
Use the quadratic formula, a =-16, b = 62, c = 2
the positive solution
t = 3.907 secs to reach the ground
