SOLUTION: In triangle ABC, (bsinC)(bcosC + ccos B) = 42. Compute the area of the triangle.
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-> SOLUTION: In triangle ABC, (bsinC)(bcosC + ccos B) = 42. Compute the area of the triangle.
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Question 1176725
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In triangle ABC, (bsinC)(bcosC + ccos B) = 42. Compute the area of the triangle.
Answer by
MathLover1(20850)
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= projection of
on
.
Then:
...height of the triangle
with respect to base
(projection of side
onto base
)
(projection of side
onto base
)
Thus
=> base
So
Therefore
square units
