SOLUTION: Integration :Find the area bounded by y=xe^-x, y=0, and x=2

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Question 1176683: Integration :Find the area bounded by y=xe^-x, y=0, and x=2

Answer by math_helper(2461) About Me  (Show Source):
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The first step is to note that the lower limit of integration will be x=0. This is because y=0 is one of the boundaries and y is negative for x<0. So we will have limits of integration of x=0 and x=2.
Use integration by parts:
Let u+=+x and +dv+=+e%5E%28-x%29dx+
giving us +du+=+dx and +v+=+-e%5E%28-x%29+

Recall integration by parts:
+int%28u+dv%29+ = u%2Av - int%28v+du%29
+int%28x+e%5E%28-x%29dx%29+ = x+%2A+%28-e%5E%28-x%29%29+ - int%28-e%5E%28-x%29+dx%29
= +-x%2Ae%5E%28-x%29%29+ - e%5E%28-x%29
= +-e%5E%28-x%29%28x%2B1%29+
Evaluate this expression at x=2: -0.4060 (approx)
and at x=0: -1
Subtract the bottom from the top: -0.4060-(-1) = 0.5940 sq units. (to 4 decimal places)