SOLUTION: Find the standard form of the equation of the hyperbola with the given characteristics.
Vertices: (±2, 0); foci: (±3, 0)
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-> SOLUTION: Find the standard form of the equation of the hyperbola with the given characteristics.
Vertices: (±2, 0); foci: (±3, 0)
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Foci is given to be, (, ) and (, ), tells us that the hyperbola is the horizontal transverse type with the equation in item 1
.... since the center is half way between foci, so it is at origin; so, and
The distance to the focus is linear eccentricity .
The point (, ) shows us the value of :
The distance to the Vertices is .
The point (, ) shows us the value of