SOLUTION: Larry is 5 years older than Mark and Andrew is 6 years older than twice Larry’s age. The sum of their ages is 57. How old is each person?

Algebra ->  Customizable Word Problem Solvers  -> Age -> SOLUTION: Larry is 5 years older than Mark and Andrew is 6 years older than twice Larry’s age. The sum of their ages is 57. How old is each person?       Log On

Ad: Over 600 Algebra Word Problems at edhelper.com


    

Question 1176549: Larry is 5 years older than Mark and Andrew is 6 years older than twice Larry’s age. The sum of
their ages is 57. How old is each person?
Found 2 solutions by ewatrrr, josgarithmetic:
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!

Hi
 Larry +  Mark  +   Andrew
 (x+ 5)+   x    +  2(x+5)+6 = 57
        4x = 36
         x = 9, Mark's age, Larry is 14  and Andrew is 34   28%2B6

 9 + 14 + 34 = 57 checks
Wish You the Best in your Studies.


Answer by josgarithmetic(39616) About Me  (Show Source):
You can put this solution on YOUR website!
PERSON               AGE
Larry                m+5
Mark                  m
Andrew               2(m+5)+6
SUM                  57

%28m%2B5%29%2Bm%2B2%28m%2B5%29%2B6=57
-
3%28m%2B5%29%2B%28m%2B6%29=57
3%28m%2B5%29%2B%28m%2B5%29%2B1=57
4%28m%2B5%29=56
m%2B5=14
highlight%28m=9%29
.
.
.
.