SOLUTION: Solve the problem. An electric company has the following rate schedule for electricity usage in single-family residences: The monthly service charge $4.93 Per kilowa

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Question 1176448: Solve the problem.
An electric company has the following rate schedule for electricity usage in single-family residences:

The monthly service charge $4.93

Per kilowatt service charge
1st 300 kilowatts $0.11589/kW
Over 300 kilowatts $0.13321/kW
What is the charge for using 300 kilowatts in one month?
What is the charge for using 375 kilowatts in one month?
Construct a function that gives the monthly charge C for x kilowatts of electricity.





Found 2 solutions by MathLover1, Solver92311:
Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!

The monthly service charge $4.93 -> constant
Per kilowatt service charge
1st 300 kilowatts $0.11589%2FkW plus $4.93

C=0.11589%2Ax%2B4.93

Over 300 kilowatts $0.13321%2FkW

C=0.13321%2Ax%2B4.93

What is the charge for using 300 kilowatts in one month?

x=300
C=0.11589%2A300%2B4.93
C=39.70

What is the charge for using 375 kilowatts in one month?

x=375
C=0.13321%2A300%2B0.13321%2A75%2B4.93
C=49.69

Answer by Solver92311(821) About Me  (Show Source):
You can put this solution on YOUR website!


You need a piece-wise function: 
        |  0.11589x + 4.93   if  x ≤ 300
C(x) =  |
        |  0.13321(x - 300) + 39.697 if x > 300


Rounded to the nearest $0.01.




John

My calculator said it, I believe it, that settles it

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