Question 1176446:  Item4 
14 
points 
eBookAskPrintItem 4 
Exercise 5-26 
Steele Electronics Inc. sells expensive brands of stereo equipment in several shopping malls. The marketing research department of Steele reports that 37% of the customers entering the store that indicate they are browsing will, in the end, make a purchase. Let the last 26 customers who enter the store be a sample.
 
 
 
a. How many of these customers would you expect to make a purchase? (Round the final answer to the nearest whole number.) 
 
 
b. What is the probability that exactly six of these customers make a purchase? (Round the final answer to 4 decimal places.) 
 
 
c. What is the probability 15 or more make a purchase? (Round the final answer to 4 decimal places.)
 
  
d. Does it seem likely at least one will make a purchase ("likely" refers if the probability is more than 70%)? 
 
  
 Answer by ikleyn(52903)      (Show Source): 
You can  put this solution on YOUR website! . 
Steele Electronics Inc. sells expensive brands of stereo equipment in several shopping malls.  
The marketing research department of Steele reports that 37% of the customers entering the store that indicate they are browsing will,  
in the end, make a purchase. Let the last 26 customers who enter the store be a sample.
 
a. How many of these customers would you expect to make a purchase? (Round the final answer to the nearest whole number.)
 
b. What is the probability that exactly six of these customers make a purchase? (Round the final answer to 4 decimal places.)
 
c. What is the probability 15 or more make a purchase? (Round the final answer to 4 decimal places.)
 
d. Does it seem likely at least one will make a purchase ("likely" refers if the probability is more than 70%)? 
~~~~~~~~~~~~~~~~
 
 
(a)  Based on given information, I expect that 37% of 26 customers, i.e.  0.37*26 = 10  (9.62 rounded) will make a purchase.    ANSWER
            For parts  b), c) and d) notice that they are binomial distribution problems 
            with the number of trial 26, the probability of success of 37% = 0.37.
(b)  In this case, I need calculate  P(n=26; k = 6; p=0.37).      
     To facilitate calculations, I use an online (free of charge) calculator at this web-site 
     https://stattrek.com/online-calculator/binomial.aspx
     It provides nice instructions  and  a convenient input and output for all relevant options/cases.
        P(n=26; k = 6; p=0.37) = 0.05730377685,   or   0.0573 (rounded).       ANSWER
     
(c)  In this case, I need calculate   P(n=26; k >= 15; p=0.37).      
     I use the same online calculator.   P(n=26; k >= 15; p=0.37) = 0.9573613397  or    0.9574  (rounded).    ANSWER
(d)  In this case, I need calculate   P(n=26; k >= 1; p=0.37).      
     I use the same online calculator.   P(n=26; k >= 1; p=0.37) = 0.99999393467  or    0.9999  (rounded).    ANSWER
 
The problem is just solved: all questions are answered.
 
 
 
 
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