SOLUTION: Item4 14 points eBookAskPrintItem 4 Exercise 5-26 Steele Electronics Inc. sells expensive brands of stereo equipment in several shopping malls. The marketing research departme

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Question 1176446: Item4
14
points
eBookAskPrintItem 4
Exercise 5-26
Steele Electronics Inc. sells expensive brands of stereo equipment in several shopping malls. The marketing research department of Steele reports that 37% of the customers entering the store that indicate they are browsing will, in the end, make a purchase. Let the last 26 customers who enter the store be a sample.

a. How many of these customers would you expect to make a purchase? (Round the final answer to the nearest whole number.)

b. What is the probability that exactly six of these customers make a purchase? (Round the final answer to 4 decimal places.)

c. What is the probability 15 or more make a purchase? (Round the final answer to 4 decimal places.)

d. Does it seem likely at least one will make a purchase ("likely" refers if the probability is more than 70%)?

Answer by ikleyn(52810) About Me  (Show Source):
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Steele Electronics Inc. sells expensive brands of stereo equipment in several shopping malls.
The marketing research department of Steele reports that 37% of the customers entering the store that indicate they are browsing will,
in the end, make a purchase. Let the last 26 customers who enter the store be a sample.
a. How many of these customers would you expect to make a purchase? (Round the final answer to the nearest whole number.)
b. What is the probability that exactly six of these customers make a purchase? (Round the final answer to 4 decimal places.)
c. What is the probability 15 or more make a purchase? (Round the final answer to 4 decimal places.)
d. Does it seem likely at least one will make a purchase ("likely" refers if the probability is more than 70%)?
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(a)  Based on given information, I expect that 37% of 26 customers, i.e.  0.37*26 = 10  (9.62 rounded) will make a purchase.    ANSWER



            For parts  b), c) and d) notice that they are binomial distribution problems 
            with the number of trial 26, the probability of success of 37% = 0.37.



(b)  In this case, I need calculate  P(n=26; k = 6; p=0.37).      


     To facilitate calculations, I use an online (free of charge) calculator at this web-site 

     https://stattrek.com/online-calculator/binomial.aspx


     It provides nice instructions  and  a convenient input and output for all relevant options/cases.


        P(n=26; k = 6; p=0.37) = 0.05730377685,   or   0.0573 (rounded).       ANSWER


     

(c)  In this case, I need calculate   P(n=26; k >= 15; p=0.37).      


     I use the same online calculator.   P(n=26; k >= 15; p=0.37) = 0.9573613397  or    0.9574  (rounded).    ANSWER




(d)  In this case, I need calculate   P(n=26; k >= 1; p=0.37).      


     I use the same online calculator.   P(n=26; k >= 1; p=0.37) = 0.99999393467  or    0.9999  (rounded).    ANSWER

The problem is just solved: all questions are answered.