SOLUTION: Find the standard form of the equation of the circle with the given characteristics. Center: (-3, 2); point on circle: (-6, 4)

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Question 1176241: Find the standard form of the equation of the circle with the given characteristics.
Center: (-3, 2); point on circle: (-6, 4)
Answer by Boreal(15235) About Me  (Show Source):
You can put this solution on YOUR website!
The radius is the sqrt (diff in x^2+ diff in y ^2)=sqrt(9+4)=sqrt(13)
change the signs of the center
(x+3)^2+(y-2)^2=13