SOLUTION: Find the sum of all positive integers from 5 to 555 inclusive, that are divisible by 5

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Question 1176091: Find the sum of all positive integers from 5 to 555 inclusive, that are divisible by 5
Answer by ikleyn(52754) About Me  (Show Source):
You can put this solution on YOUR website!
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This sum is equal to five times the sum of all natural integer numbers from 1 to 111, inclusive.


So, the answer is  5%2A%28%28111%2A112%29%2F2%29%29 = 31080.

Solved.

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This problem is on Arithmetic progressions.


For introductory lessons on arithmetic progressions see
    - Arithmetic progressions
    - The proofs of the formulas for arithmetic progressions
    - Problems on arithmetic progressions
    - Word problems on arithmetic progressions
in this site.

Also,  you have this free of charge online textbook in ALGEBRA-II in this site
    - ALGEBRA-II - YOUR ONLINE TEXTBOOK.

The referred lessons are the part of this online textbook under the topic "Arithmetic progressions".


Save the link to this textbook together with its description

Free of charge online textbook in ALGEBRA-II
https://www.algebra.com/algebra/homework/complex/ALGEBRA-II-YOUR-ONLINE-TEXTBOOK.lesson

into your archive and use when it is needed.