SOLUTION: In 11.4 days a certain amount of iodine - 131 has decayed to (1/√2) of its original amount. What is the half-life of iodine - 131?

Algebra ->  Trigonometry-basics -> SOLUTION: In 11.4 days a certain amount of iodine - 131 has decayed to (1/√2) of its original amount. What is the half-life of iodine - 131?      Log On


   

Question 1176084: In 11.4 days a certain amount of iodine - 131 has decayed to (1/√2) of its original amount. What is the half-life of iodine - 131?
Answer by ikleyn(52800) About Me  (Show Source):
You can put this solution on YOUR website!
.

Notice that  %281%2Fsqrt%282%29%29%2A%281%2Fsqrt%282%29%29 = 1%2F2.


It means that half-life of iodine-131 is two times 11.4 days,  or  2*11.4 = 22.8 days.    ANSWER

Solved.

--------------------

To learn more on the subject,  look into the lesson
    - Radioactive decay problems
in this site.

Also,  you have this free of charge online textbook in ALGEBRA-I in this site
    - ALGEBRA-I - YOUR ONLINE TEXTBOOK.

The referred lesson is the part of this online textbook under the topic "Logarithms".


Save the link to this online textbook together with its description

Free of charge online textbook in ALGEBRA-I
https://www.algebra.com/algebra/homework/quadratic/lessons/ALGEBRA-I-YOUR-ONLINE-TEXTBOOK.lesson

to your archive and use it when it is needed.


////////////


By the way,  the  Internet sources give  ANOTHER  value for the  Iodine-131  half-life:   8 days.

So,  your input data is  INCORRECT.


See,  for example,  these sources

https://en.wikipedia.org/wiki/Iodine-131

https://www.radioactivity.eu.com/site/pages/Iodine_131.htm