SOLUTION: A trapezoidal room is to be tiled. The bases are 90 feet and 100 feet, and the height is 30 feet. What is the cost if the tile costs $1.10 per square foot?

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Question 1176072: A trapezoidal room is to be tiled. The bases are 90 feet and 100 feet, and the
height is 30 feet. What is the cost if the tile costs $1.10 per square foot?
Found 2 solutions by MathLover1, Edwin McCravy:
Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!
trapeziod
bases a=90ft and b=100ft
height h=30ft
A+=+%28a+%2B+b%29+%2A+h%2F2
A+=+%2890ft+%2B+100ft%29+%2A+30ft%2F2
A+=+190%2A15ft%5E2
A+=+2850ft%5E2
cost $1.10 per ft%5E2
cost $2850%2A1.10= $3,135.00


Answer by Edwin McCravy(20063) About Me  (Show Source):
You can put this solution on YOUR website!
A trapezoidal room is to be tiled. The bases are 90 feet and 100 feet, and the
height is 30 feet. What is the cost if the tile costs $1.10 per square foot? 

First we average the bases by adding them and taking half

adding the bases gives 90+100 = 190
Dividing by 2 gives 95 for the average base

So we plug in the formula:



Then we multiply by $1.10 per sq. ft.



Edwin