SOLUTION: Solve: (ax - b) / c - (bx + c) / a = abc axc - bca - bxac + ac = a^2bc^2 Not sure how to solve.

Algebra ->  Customizable Word Problem Solvers  -> Misc -> SOLUTION: Solve: (ax - b) / c - (bx + c) / a = abc axc - bca - bxac + ac = a^2bc^2 Not sure how to solve.      Log On

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Question 1176070: Solve:
(ax - b) / c - (bx + c) / a = abc
axc - bca - bxac + ac = a^2bc^2


Not sure how to solve.
Answer by math_helper(2461) About Me  (Show Source):
You can put this solution on YOUR website!



++%28ax+-+b%29+%2F+c+-+%28bx+%2B+c%29+%2F+a+ = +abc++



Multiply both sides by ac:

++a%28ax-b%29+-+c%28bx%2Bc%29+ = +a%5E2bc%5E2+



Expand LHS:

+%28a%5E2x-ab%29+-+%28bcx+%2Bc%5E2%29+ = +a%5E2bc%5E2+



We are solving for x, right?  Bring terms involving 'x' together,

move others to RHS:

++%28a%5E2x+-+bcx%29+ = +a%5E2bc%5E2+%2Bab+%2Bc%5E2+



Factor out 'x':

++%28a%5E2+-+bc%29x+ = +a%5E2bc%5E2+%2Bab+%2Bc%5E2+



Divide both sides by +a%5E2-bc+

+++x+ = +%28+a%5E2bc%5E2+%2Bab+%2Bc%5E2+%29%2F+%28+a%5E2+-+bc+%29+  ; +a%5E2-bc+%3C%3E+0+





EDIT: fixed sign error on c^2 on RHS (had -, should have been +)