SOLUTION: A purse contains 26 coins, some of which are dimes and the rest nickels. Altogether, the coins are worth more than $2.10. At least how many dimes are in the purse?

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Question 1175926: A purse contains 26 coins, some of which are dimes and the rest nickels. Altogether, the coins are worth more than $2.10. At least how many dimes are in the purse?
Found 2 solutions by CubeyThePenguin, ikleyn:
Answer by CubeyThePenguin(3113) About Me  (Show Source):
You can put this solution on YOUR website!
d = number of dimes
n = number of nickels

d + n = 26 (eqn 1)
10d + 5n = 210 (eqn 2)

Multiply equation 1 by 10.

10d + 10n = 260
10d + 5n = 210

Subtract the two to get 5n = 50. So, there are 10 nickels and 16 dimes in the purse.

Answer by ikleyn(52914) About Me  (Show Source):
You can put this solution on YOUR website!
.
A purse contains 26 coins, some of which are dimes and the rest nickels. Altogether, the coins
are worth more than $2.10. At least how many dimes are in the purse?
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Let the number of dimes be " d ".

Then the number of nickels is (26-d).


The total money inequality is


    10d + 5(26-d) > 210  cents.


Simplify and solve


    10d + 5*26 - 5d > 210

          5d        > 210 - 5*26

          5d        >    80

           d        >    80/5 = 16


ANSWER.  The number of dimes is at least 17.