You can put this solution on YOUR website! Find two consecutive numbers
n, (n+1)
whose product is 210
n(n+1) = 210
arrange as a quadratic equation
n^2 + n - 210 = 0
factors to
(n+15)(n-14) = 0
n = -15, consecutive numbers -15,-14
or
n = +14, consecutive numbers 14, 15