SOLUTION: 37% of the squirrels in Cititon Park are gray. What is the probability that, in a random sample of 174 squirrels, less than 64 are gray squirrels? Use a normal approximation to com
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Question 1175796: 37% of the squirrels in Cititon Park are gray. What is the probability that, in a random sample of 174 squirrels, less than 64 are gray squirrels? Use a normal approximation to compute your answer. Round your answer to 4 decimal places. Answer by Boreal(15235) (Show Source):
You can put this solution on YOUR website! mean=np=60.68 squirrels
variance=np(1-p)=60.68*0.63=38.23 squirrels^2
sd=sqrt(V)=6.18 squirrels
z < (63.5-60.68)/6.18, using the continuity correction factor for < 64
z < 2.82/6.18=0.456
probability is 0.6758
