SOLUTION: According to the last census, 45% of working women held full-time jobs in 2010. If a random sample of 50 working women is drawn, what is the probability that 19 𝑜𝑟 𝑚𝑜
Algebra ->
Probability-and-statistics
-> SOLUTION: According to the last census, 45% of working women held full-time jobs in 2010. If a random sample of 50 working women is drawn, what is the probability that 19 𝑜𝑟 𝑚𝑜
Log On
Question 1175793: According to the last census, 45% of working women held full-time jobs in 2010. If a random sample of 50 working women is drawn, what is the probability that 19 𝑜𝑟 𝑚𝑜𝑟𝑒 hold full-time jobs? Found 2 solutions by ewatrrr, ikleyn:Answer by ewatrrr(24785) (Show Source):
Hi
Binomial Distribution: p = .45 and q = .55 (not full-time)
n = 50
P(x ≥ 19) = 1 - P(x ≤ 18) = bin0mcdf(50, .45, 18) = 1 - .1273 = .8727
Wish You the Best in your Studies.