SOLUTION: According to the last census, 45% of working women held full time jobs in 2010. If a random sample of 50 working women is drawn, what is the probability that 19 or more hold full t
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Question 1175758: According to the last census, 45% of working women held full time jobs in 2010. If a random sample of 50 working women is drawn, what is the probability that 19 or more hold full time jobs? Answer by ikleyn(52818) (Show Source):
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According to the last census, 45% of working women held full time jobs in 2010. If a random sample
of 50 working women is drawn, what is the probability that 19 or more hold full time jobs?
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It is a binomial distribution probability problem.
- number of trials n = 50;
- number of success trial k >= 19;
- Probability of success on a single trial p = 0.45.
We need calculate P(n=50; k>=19; p=0.45) = 0.531441.
To facilitate calculations, I use an appropriate online (free of charge) calculator at this web-site
https://stattrek.com/online-calculator/binomial.aspx
It provides nice instructions and a convenient input and output for all relevant options/cases.
P(n=50; k>=19; p=0.45) = 0.87265488533, or 0.8727 (rounded). ANSWER
