SOLUTION: Evaluate each function for the value specified. f(x)=x^-7x+10; find (a) f(0), (b) f(5), (c) f(-2). This is what I have: f(x)=2^(-7x+10) (a) f(0)=2^(-7*0+10=2^(0+10)=2^+10=1024

Algebra ->  Linear-equations -> SOLUTION: Evaluate each function for the value specified. f(x)=x^-7x+10; find (a) f(0), (b) f(5), (c) f(-2). This is what I have: f(x)=2^(-7x+10) (a) f(0)=2^(-7*0+10=2^(0+10)=2^+10=1024       Log On


   

Question 117574: Evaluate each function for the value specified.
f(x)=x^-7x+10; find (a) f(0), (b) f(5), (c) f(-2).
This is what I have: f(x)=2^(-7x+10)
(a) f(0)=2^(-7*0+10=2^(0+10)=2^+10=1024
(b) f(5)=2^(-7*5+10)=2^-25=1/(2*25)
(c) f(-2)=2^(-7*-2+10)=2^(14+10)=2*24
My question is, am I correct on these solutions?
Thank You, Barb Neely
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
Is your function x%5E2-7x%2B10? If it is, then....



Let's evaluate f%280%29


f%28x%29=x%5E2-7x%2B10 Start with the given function.


f%280%29=%280%29%5E2-7%280%29%2B10 Plug in x=0. In other words, replace each x with 0.


f%280%29=%280%29-7%280%29%2B10 Evaluate %280%29%5E2 to get 0.


f%280%29=%280%29%2B0%2B10 Multiply -7 and 0 to get 0


f%280%29=10 Now combine like terms


-----------Now let's evaluate another value---------


Let's evaluate f%285%29


f%28x%29=x%5E2-7x%2B10 Start with the given function.


f%285%29=%285%29%5E2-7%285%29%2B10 Plug in x=5. In other words, replace each x with 5.


f%285%29=%2825%29-7%285%29%2B10 Evaluate %285%29%5E2 to get 25.


f%285%29=%2825%29-35%2B10 Multiply -7 and 5 to get -35


f%285%29=0 Now combine like terms


-----------Now let's evaluate another value---------


Let's evaluate f%28-2%29


f%28x%29=x%5E2-7x%2B10 Start with the given function.


f%28-2%29=%28-2%29%5E2-7%28-2%29%2B10 Plug in x=-2. In other words, replace each x with -2.


f%28-2%29=%284%29-7%28-2%29%2B10 Evaluate %28-2%29%5E2 to get 4.


f%28-2%29=%284%29%2B14%2B10 Multiply -7 and -2 to get 14


f%28-2%29=28 Now combine like terms