SOLUTION: Find the equation of the sphere with diameter endpoints (2,-7,-2) and (-4,3,2).

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Question 1175624: Find the equation of the sphere with diameter endpoints (2,-7,-2) and (-4,3,2).
Answer by ikleyn(52884) About Me  (Show Source):
You can put this solution on YOUR website!
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Find the equation of the sphere with diameter endpoints A = (2,-7,-2) and B = (-4,3,2).
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The center is the point  (-1,-2,0)  (for each coordinate, you take half the sum of respective coordinates of the given points).


The diameter  AB  is the vector with components (-6,10,4);  so its length is


    sqrt%28%28-6%29%5E2+%2B+10%5E2+%2B+4%5E2%29 = sqrt%2836+%2B+100+%2B+16%29 = sqrt%28152%29 = 2%2Asqrt%2838%29  units long,


so the radius is  sqrt%2838%29  units long.


Thus the standard equation for the sphere is


    %28x%2B1%29%5E2 + %28y%2B2%29%5E2 + z%5E2 = 38.

Solved.