Question 1175622: f(x) log1.3+1
evaluate the f(30,000)
Answer by ikleyn(52787)   (Show Source):
You can put this solution on YOUR website! .
f(x) log1.3+1
evaluate the f(30,000)
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Notice that the sign " = " absents, so f(x) is not defined.
Also notice that in the first line variable x absents; THEREFORE, everything to the right of f(x) is simply constant value.
Revise your post.
After revising and editing, you can re-post it to the forum.
If you re-post, PLEASE do not post it to me personally.
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Think how much my time I spent for nothing explaining you why your job was done incorrectly. . .
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