SOLUTION: Translate to an algebra statement; do not solve: Three times the sum of a number and seven yields the same result as the twice the same number decreased by four.

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Question 117562: Translate to an algebra statement; do not solve:
Three times the sum of a number and seven yields the same result as the twice the same number decreased by four.
Found 2 solutions by jim_thompson5910, bucky:
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
Let x=some number

"Three times the sum of a number and seven "----> 3%28x%2B7%29


"twice the same number decreased by four" ---->2x-4


Putting this altogether, we get


3%28x%2B7%29=2x-4

Answer by bucky(2189) About Me  (Show Source):
You can put this solution on YOUR website!
"a number" suggests that you have an unknown number. Represent it by x.
.
The sum of "a number" and 7, can therefore be represented by (x + 7). Then 3 times that is:
3(x + 7).
.
"Yields the same result as" is just a fancy way of saying "equals" ... So up to this point
you have:
.
3(x + 7) =
.
Next, twice the same number is 2x and that decreased by 4 is 2x - 4. So the total algebraic
statement becomes:
.
3(x + 7) = 2x - 4
.