Question 1175615: Hi
A had 52 dollars more than B.B had 3 times as much as C. If C had 100 dollars less than A how much money did they have altogether.
Thank you
Found 2 solutions by Theo, ikleyn:
Answer by Theo(13342)   (Show Source):
You can put this solution on YOUR website! let a equal the amount that A had.
let b equal the amount that B had.
let C equal the amount that C had.
yu are given that:
a = b + 52
b = 3c
c = a - 100
in the first 2 equations, replace b with 3c to get:
a = b + 52 becomes a = 3c + 52
in the third equation, replace a with 3c + 52 to get:
c = a - 100 becomes c = 3c + 52 - 100.
combine like terms to get:
c = 3c - 48
subtract c from both sides of the equation and add 48 to both sides of the equation to get:
48 = 2c
solve for c to get:
c = 24
in the equation that says b = 3c, replace c with 24 to get:
b = 3 * 24.
solve for b to get:
b = 72.
in the equation that says a = b + 52, replace b with 72 to get:
a = 72 + 52 = 124.
your now have:
a = 124
b = 72
c = 24
add then up and you have a + b + c = 220.
that's your solution.
Answer by ikleyn(52817)  (Show Source):
You can put this solution on YOUR website! .
Let C = x;
then B = 3x and A = 3x+52.
You are given
A - C = 100, or
(3x + 52) - x = 100,
2x = 100-52 = 48
x = 48/2 = 24.
C had 24 dollars; B had 3*24 = 72 dollars; A had 72 + 52 = 124 dollars.
Together, they had 24 + 72 + 124 = 220 dollars. ANSWER
Solved.
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