SOLUTION: A hospital administrator deposits $10,000 into an account that earns 9% annual interest compounded monthly. In approximately how many years will the investment be worth $18,000? Ro

Algebra ->  Exponential-and-logarithmic-functions -> SOLUTION: A hospital administrator deposits $10,000 into an account that earns 9% annual interest compounded monthly. In approximately how many years will the investment be worth $18,000? Ro      Log On


   



Question 1175582: A hospital administrator deposits $10,000 into an account that earns 9% annual interest compounded monthly. In approximately how many years will the investment be worth $18,000? Round to the nearest whole number.
Answer by Theo(13342) About Me  (Show Source):
You can put this solution on YOUR website!
formula to use is f = p * (1 + r) ^ n
f is the future value
p is the present value
r is the interest rate per time period
n is the number of time periods.

in this problem:

f = 18,000
p = 10,000
r = 9% per year divided by 12 = .75% / 100 = .0075 per month
the formula requires the rate, not the percent.
n = what you want to find.

the formula becomes:

18,000 = 10,000 * 1.0075 ^ n

divide both sides of the equation by 10,000 to get:

1.8 = 1.0075 ^ n

take the log of both sides of the equation to get:

log(1.8) = log(1.0075 ^ n)

by the law of logs that says log(x^n) = n * log(x), the equation becomes:

log(1.8) = n * log(1.0075)

divide both sides of the equation by log(1.0075) to get:

log(1.8) / log(1.0075) = n

solve for n to get:

n = 78.66508266 months.

confirm by replacing n in the original equation and solving for f.

equation becomes f = 10,000 * 1.0075 ^ 78.66508266 = 18,000.

this confirms the answer is correct.

divide the number of months by 12 to get 6.55542355 years.

round to the nearest whole number to get 7.

that's your solution.

on a graph, it looks like this.



the number of years is 6.55.....

that's after the end of the 6th year which puts the solution in the 7th year.