SOLUTION: How many liters of a 50% acid solution must be mixed with a 15% acid solution to get 350 L of a 40% acid solution?

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Question 1175578: How many liters of a 50% acid solution must be mixed with a 15% acid solution to get 350 L of a 40% acid solution?
Answer by ikleyn(52798) About Me  (Show Source):
You can put this solution on YOUR website!

    0.5x + 0.15*(350-x) = 0.4*350


      x = %280.4%2A350+-+0.15%2A350%29%2F%280.5-0.15%29 = 250 L.


ANSWER.  250 liters.

Solved.

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It is a standard and typical mixture problem.

In this site, there is a bunch of lessons,  covering various types of mixture problems.  See introductory lessons
    - Mixture problems
    - More Mixture problems
    - Solving typical word problems on mixtures for solutions
    - Word problems on mixtures for antifreeze solutions
    - Word problems on mixtures for alloys
    - Typical word problems on mixtures from the archive

Read them and become an expert in solution the mixture word problems.

Also,  you have this free of charge online textbook in ALGEBRA-I in this site
    - ALGEBRA-I - YOUR ONLINE TEXTBOOK.

The referred lessons are the part of this online textbook under the topic "Mixture problems".


Save the link to this online textbook together with its description

Free of charge online textbook in ALGEBRA-I
https://www.algebra.com/algebra/homework/quadratic/lessons/ALGEBRA-I-YOUR-ONLINE-TEXTBOOK.lesson

to your archive and use it when it is needed.