SOLUTION: If 0° < A, B < 90°, and sin A = cos B, what is the value of cot (A+B)?

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Question 1175562: If 0° < A, B < 90°, and sin A = cos B, what is the value of cot (A+B)?
Answer by ikleyn(52794) About Me  (Show Source):
You can put this solution on YOUR website!
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If 0° < A, B < 90°, and sin A = cos B, then  A + B = pi%2F2.


THEREFORE,  cot (A+B) = cot%28pi%2F2%29 = 0.    ANSWER

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