SOLUTION: Is it possible to solve the following system of equations through substitution. If it is, then list the values for x, y, and z. -4x+5y-3z=17 -3x-2y-4z=-1 5x+5y+4z=12

Algebra ->  Expressions-with-variables -> SOLUTION: Is it possible to solve the following system of equations through substitution. If it is, then list the values for x, y, and z. -4x+5y-3z=17 -3x-2y-4z=-1 5x+5y+4z=12      Log On


   



Question 1175559: Is it possible to solve the following system of equations through substitution. If it is, then list the values for x, y, and z.
-4x+5y-3z=17
-3x-2y-4z=-1
5x+5y+4z=12

Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!

-4x%2B5y-3z=17.....eq.1
-3x-2y-4z=-1.....eq.2
5x%2B5y%2B4z=12.....eq.3
----------------------------------------
start with
5x%2B5y%2B4z=12.....eq.3
-4x%2B5y-3z=17.....eq.1
-------------------------------------------subtract eq.1 from eq.3
5x%2B5y%2B4z-%28-4x%2B5y-3z%29=12-17.....eq.3
5x%2B5y%2B4z%2B4x-5y%2B3z=-5
9x%2B7z=-5....solve for x
9x=-7z-5
x=-7z%2F9-5%2F9.....eq.1a

go to
-3x-2y-4z=-1.....eq.2
5x%2B5y%2B4z=12.....eq.3
-------------------------------------------add eq.2 from eq.3
5x%2B5y%2B4z%2B%28-3x-2y-4z%29=12%2B%28-1%29
5x%2B5y%2B4z-3x-2y-4z=11
2x%2B3y=11...solve for x
2x=11-3y
x=11%2F2-3y%2F2.....eq.1b

from eq.1a and eq.1b we have
-7z%2F9-5%2F9=11%2F2-3y%2F2..solve for y
3y%2F2=11%2F2%2B7z%2F9%2B5%2F9
3y%2F2=%287+z%29%2F9+%2B+109%2F18
y=%282%2F3%29%287+z%29%2F9+%2B+%282%2F3%29109%2F18
y=%2814+z%29%2F27+%2B+109%2F27.....eq.1c

go to
x=11%2F2-3y%2F2.....eq.1b, substitute y
x=11%2F2-3%28%2814+z%29%2F27+%2B+109%2F27%29%2F2
x=11%2F2-%283%2F2%29%28%2814+z%29%2F27+%2B+109%2F27%29..........1d

-3x-2y-4z=-1.....eq.2, substitute x and y from 1d and 1c

-1%2F27+%2873+z+%2B+173%29=-1
-1+%2873+z+%2B+173%29=-27
-73+z+-+173=-27
27-+173=73+z
-146=73+z
z=-146%2F73+
z=-2+

go to
y=%2814+z%29%2F27+%2B+109%2F27.....eq.1c, substitute z
y=%2814%28-2%29%29%2F27+%2B+109%2F27
y=-28%2F27+%2B+109%2F27
y=81%2F27
y=3

go to
x=11%2F2-3y%2F2.....eq.1b, substitute y
x=11%2F2-%283%2A3%29%2F2
x=11%2F2-9%2F2
x=2%2F2
x=1

solution set:
x=1
y=3
z=-2+