SOLUTION: A Food Marketing Institute found that 26% of households spend more than $125 a week on groceries. Assume the population proportion is 0.26 and a simple random sample of 52 househol
Algebra ->
Probability-and-statistics
-> SOLUTION: A Food Marketing Institute found that 26% of households spend more than $125 a week on groceries. Assume the population proportion is 0.26 and a simple random sample of 52 househol
Log On
Question 1175543: A Food Marketing Institute found that 26% of households spend more than $125 a week on groceries. Assume the population proportion is 0.26 and a simple random sample of 52 households is selected from the population. What is the probability that the sample proportion of households spending more than $125 a week is between 0.23 and 0.5? Answer by Boreal(15235) (Show Source):
You can put this solution on YOUR website! This is z (0.23-0.26)/sqrt(.26*.74/52)
=-0.49
and z (0.50-0.26)/sqrt(.26*.74/52)
=3.94
probability is 0.6879
