SOLUTION: Solve for y when x=10+4z/10. a. 2x+y-z=2 I tried the following: 2(10+4z/10)+y-z=2 20+8z/20+y-z=2 20(20+8z/20+y-z=2) 20+8z+20y-20z=20 -14z+20-20=-20y -14z=-20y -14z/-

Algebra ->  Expressions-with-variables -> SOLUTION: Solve for y when x=10+4z/10. a. 2x+y-z=2 I tried the following: 2(10+4z/10)+y-z=2 20+8z/20+y-z=2 20(20+8z/20+y-z=2) 20+8z+20y-20z=20 -14z+20-20=-20y -14z=-20y -14z/-      Log On


   

Question 1175535: Solve for y when x=10+4z/10.
a. 2x+y-z=2
I tried the following:
2(10+4z/10)+y-z=2
20+8z/20+y-z=2
20(20+8z/20+y-z=2)
20+8z+20y-20z=20
-14z+20-20=-20y
-14z=-20y
-14z/-20=y
7/10=y
Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!

Solve for y .
a.
2x%2By-z=2.....when x=10%2B4z%2F10
2%2810%2B4z%2F10%29%2By-z=2
20%2B8z%2F10%2By-z=2
20%2B8z%2F10%2By-10z%2F10=2
20%2By-z%2F5=2
y=2-20%2Bz%2F5
y=z%2F5-18