SOLUTION: One number is twice another number. Twice the lesser number increased by the greater number is at least 45. What is the least possible integral value for the lesser number?

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Question 1175442: One number is twice another number. Twice the lesser number increased by the greater number is at least 45. What is the least possible integral value for the lesser number?

Answer by Edwin McCravy(20060) About Me  (Show Source):
You can put this solution on YOUR website!
It is not necessary to state that the lesser number is positive, since
if it were negative, both the lesser and greater would be negative, and
you cannot increase a negative with a negative.  And 0 is out because
twice zero is zero, and there could be no lesser and greater.

x = lesser (positive) integer
2x = greater integer

2x + 2x ≥ 45
     4x ≥ 45
      x ≥ 11.25

Since x is an integer, x=12.  

Edwin